Math, asked by negimansi277, 1 month ago

Find the remainder when x3+3x2+3x+1 is divided by x+1 by long division method

Answers

Answered by sharmakush976
0

Answer:

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Answered by archanatyagi10041980
0

Answer:

Dividend = x³+3x²+3x+1

Dividend = x³+3x²+3x+1Divisor = x - 1/2

Dividend = x³+3x²+3x+1Divisor = x - 1/2Quotient = x² + 7x/2 + 19/4

Dividend = x³+3x²+3x+1Divisor = x - 1/2Quotient = x² + 7x/2 + 19/4Remainder = 27/8

Step-by-step explanation:

\begin{gathered} Given \\ (x^{3}+3x^{2}+3x+1)\div (x-\frac{1}{2})\end{gathered}

Given

(x

3

+3x

2

+3x+1)÷(x−

2

1

)

Quotient :x²+7x/2+19/4

x-1/2)x³+3x²+3x+1(

***** x³ -x²/2

____________________

******** 7x²/2 +3x

******** 7x²/2 -7x/4

_________________________

************** 19x/4 +1

************** 19x/4 -19/8

___________________________

********Remainder (27/8)

Therefore,

Dividend = x³+3x²+3x+1

Divisor = x - 1/2

Quotient = x² + 7x/2 + 19/4

Remainder = 27/8

•••♪

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