Find the remainder when x3+3x2+3x+1 is divided by x+1 by long division method
Answers
Answer:
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Answer:
Dividend = x³+3x²+3x+1
Dividend = x³+3x²+3x+1Divisor = x - 1/2
Dividend = x³+3x²+3x+1Divisor = x - 1/2Quotient = x² + 7x/2 + 19/4
Dividend = x³+3x²+3x+1Divisor = x - 1/2Quotient = x² + 7x/2 + 19/4Remainder = 27/8
Step-by-step explanation:
\begin{gathered} Given \\ (x^{3}+3x^{2}+3x+1)\div (x-\frac{1}{2})\end{gathered}
Given
(x
3
+3x
2
+3x+1)÷(x−
2
1
)
Quotient :x²+7x/2+19/4
x-1/2)x³+3x²+3x+1(
***** x³ -x²/2
____________________
******** 7x²/2 +3x
******** 7x²/2 -7x/4
_________________________
************** 19x/4 +1
************** 19x/4 -19/8
___________________________
********Remainder (27/8)
Therefore,
Dividend = x³+3x²+3x+1
Divisor = x - 1/2
Quotient = x² + 7x/2 + 19/4
Remainder = 27/8
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