find the remainder when x3+3x2+3x+1 is divided by x+1 short cut
Answers
Answered by
5
Hey dear !!!
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Let's solve it by factor theorem!!
==>> In the example
p(x) = x³ + 3x² + 3x + 1 is divided by ( x + 1 )
x = -1 taking
p(-1) = (-1)³ + 3(-1)² + 3(-1) + 1
= -1 + 3 * 1 - 3 + 1
= -1 + 3 - 3 + 1
= 2 - 3 + 1
= - 1 + 1
= 0
∴ The Remainder will be 0 .
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Let's solve it by factor theorem!!
==>> In the example
p(x) = x³ + 3x² + 3x + 1 is divided by ( x + 1 )
x = -1 taking
p(-1) = (-1)³ + 3(-1)² + 3(-1) + 1
= -1 + 3 * 1 - 3 + 1
= -1 + 3 - 3 + 1
= 2 - 3 + 1
= - 1 + 1
= 0
∴ The Remainder will be 0 .
Answered by
1
Hey user here is your answer ........
-----> To divide - x^3+3x^2+3x+1 by x+1
◆ X+1=0
●x=-1
◆Put value of x in given expression
◆P(-1)=(-1)^3+3(-1)^2+3(-1)+1
◆P(-1)= (-1)+(3)+(-3)+1
-----> Open brackets
◆P(-1)=-1+3-3+1
◆P(-1)=0
◆So here remainder is 0.
Hope it helps you☺️
-----> To divide - x^3+3x^2+3x+1 by x+1
◆ X+1=0
●x=-1
◆Put value of x in given expression
◆P(-1)=(-1)^3+3(-1)^2+3(-1)+1
◆P(-1)= (-1)+(3)+(-3)+1
-----> Open brackets
◆P(-1)=-1+3-3+1
◆P(-1)=0
◆So here remainder is 0.
Hope it helps you☺️
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