Math, asked by jaiagarwal8765, 9 months ago

Find the remainder when x³+ 3x²+ 3x+ 1 is divided by
x+1
x-1
x+π
5+2x

Answers

Answered by MaheswariS
2

Answer:

\bf\text{Remainder theorem}

\boxed{\text{The remainer when P(x) is divided by (x-a) is P(a)}}

P(x)=x^3+3x^2+3x+1

1.

\text{The remainder when P(x) is divided by (x+1) is P(-1)}

P(-1)=(-1)^3+3(-1)^2+3(-1)+1

P(-1)=-1+3-3+1

P(-1)=0

2.

\text{The remainder when P(x) is divided by (x-1) is P(1)}

P(1)=(1)^3+3(1)^2+3(1)+1

P(1)=1+3+3+1

P(1)=8

3.

\text{The remainder when P(x) is divided by }(x+\pi)\:is\:P(-\pi)

P(-\pi)=(-\pi)^3+3(\pi)^2+3(\pi)+1

P(-\pi)=-{\pi}^3+3(\pi)^2+3(\pi)+1

4.

\text{The remainder when P(x) is divided by (2x+5) is }P(\frac{-5}{2})

P(\frac{-5}{2})=(\frac{-5}{2})^3+3(\frac{-5}{2})^2+3(\frac{-5}{2})+1

P(\frac{-5}{2})=\frac{-125}{8}+3(\frac{25}{4})-\frac{15}{2}+1

P(\frac{-5}{2})=\frac{-125+150-60+8}{8}

P(\frac{-5}{2})=\frac{-27}{8}

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