find the remainder when x³+3x²+3x+1 is divided by x
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The remainder theorem, 27 / 8 is the remainder when x3 + 3x2 + 3x + 1 is divided by x. Hence by the remainder theorem, 1 is the remainder when x3 + 3x2 + 3x + 1 is divided by x. Hence by the remainder theorem, -π3 + 3π2 - 3π + 1 is the remainder when x3 + 3x2 + 3x +1 is divided by x + π
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