Find the remainder when x³-3x²+3x-1is divided by x+3
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Answer:
Remainder = -64
Step-by-step explanation:
By remainder theorem
Given,
(x + 3) i.e, x + 3 = 0. therefore, x = -3
let f(x) = x³ - 3x² + 3x - 1 [now put the value of x]
f(-3) = (-3)³ - 3(-3)² + 3 x (-3) - 1
= {(-3) x (-3) x (-3)} - {3 x (-3) x (-3)} - 9 - 1
= (-27) - 27 - 10
= -64
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