Question

find the remainder when x³+3x²+3x+2 is divided by x-7​

Answer 1

Answer:

709

Step-by-step explanation:

Taking x-7 = 0, x = 7

Now, substituting the value of x

7³ + 3 (7)² + 3(7) + 2

= 343 + 343 + 21 + 2

= 709

Answer 2

Given :

A dividend $x^{3} +3x^{2} +3x+2$ and divisor $x-7$.

To find :

To find the remainder.

Step-by-step explanation:

• The remainder can be found by following these steps.
• The divisor value must be equated to $0$.

        $x-7=0$

• Take the number to the other side of the equation.

        $x=7$

• The value of $x$ must be substituted in the expression of dividend.
• The dividend expression is

        $x^{3} +3x^{2} +3x+2$

• Substitute the value of x

        $(7)^{3} +3(7)^{2} +3(7)+2$

• Square the values.

        $343+147+21+2$

• Sum the values

        $513$

Final answer :

The remainder for the dividend $x^{3} +3x^{2} +3x+2$ and divisor $x-7$ is $513.$