Question

find the remainder when (x3+4x-5) is divided by (x-1)

Answer 1

the remainder is 0
hope it's help you

Answer 2

Step-by-step explanation:

Given: If $p(x) = {x}^{3} + 4x - 5$

is divided by $(x - 1)$.

To find: Find the remainder.

Solution:

Divide p(x) by $(x - 1)$

$x - 1 \: ) \: {x}^{3} + 4x - 5 \: ( {x}^{2} + x + 5 \\ {x}^{3} \: \: \: \: \: \: \: \: \: \: - {x}^{2} \\ - - - - - - - \\ {x}^{2} + 4x - 5 \\ {x}^{2} - x \: \: \: \: \: \: \: \: \: \\ - - - - - \\ 5x - 5 \\ 5x - 5 \\ - - - - - \\ 0 \\ - - - - -$

Remainder is zero.

Final answer:

If $p(x)=( {x}^{3} +4x-5)$ is divided by $( x-1)$, then remainder is 0.

Hope it helps you.

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