Question

find the remainder,when x3+4x2-5x2-6x+7 is divided by x-3
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Answer 1

Answer:

sorry I don't know how to make a good time

Answer 2

Step-by-step explanation:

$\frac{ {x}^{3} + 4 {x}^{2} - 5 {x}^{2} - 6x + 7 }{x - 3}$

$= \frac{ {x}^{3} - {x}^{2} - 6x + 7}{x - 3}$

remainder will be 7 bro