Question

Find the remainder when x³-6x²+11x-6 is divided by:

1. x-1
2. x+1
3. x+2
4. x-3​

Answer 1

Step-by-step explanation:

x-1=0 so

x=1 put this value in equation

(1)*3-6(1)*2+11(1)-6

1-6+11-6=0 so in this case remainder is 0.

similarly

$x + 1 \div {x}^{3} - 6 {x}^{2} + 11x - 6 \\ x + 1 = 0 \\ x = - 1 \\ put \: this \: value \\ { - 1}^{3} - 6( { - 1)}^{2 } + 11( - 1) - 6 \\ - 1 - 6 - 11 - 6 \\ - 25$