Question

find the remainder when x3-6x2+2x-4 is divided by 1-2x by remainder theorem​

Answer 1

Answer:

The zero of g(x)=1−2x is x= 2/1

Now, by remainder theorem the remainder should be f(1/2)

Therefore,

f(1/2) = (1/2)3 -6(1/2)2 +2(1/2) -4

=(1/8)- 6(1/4)+1-4

=(1/8)- (6/4)-3

= 1-12-24/8

= -35/8

Answer 2

Answer:

Quotient = 1/2x²-11/4x-3/8

remainder = -35/8

Step-by-step explanation:

1-2x = 2x-1

___________

2x-1 ) x³-6x²+2x-4 ( 1/2x²-11/4x-3/8

x³-1/2x²

(-) (+)

———————–

-11/2x²+2x -4

-11/2x²+11/4x

(+) (-)

————––—–—

-3/4x-4

-3/4x+3/8

(+) (-)

—–—–—–—

-35/8