find the remainder when x3-6x2+2x-4 is divided by 1-2x by remainder theorem
Answers
Answered by
3
Answer:
The zero of g(x)=1−2x is x= 2/1
Now, by remainder theorem the remainder should be f(1/2)
Therefore,
f(1/2) = (1/2)3 -6(1/2)2 +2(1/2) -4
=(1/8)- 6(1/4)+1-4
=(1/8)- (6/4)-3
= 1-12-24/8
= -35/8
Answered by
2
Answer:
Quotient = 1/2x²-11/4x-3/8
remainder = -35/8
Step-by-step explanation:
1-2x = 2x-1
___________
2x-1 ) x³-6x²+2x-4 ( 1/2x²-11/4x-3/8
x³-1/2x²
(-) (+)
———————–
-11/2x²+2x -4
-11/2x²+11/4x
(+) (-)
————––—–—
-3/4x-4
-3/4x+3/8
(+) (-)
—–—–—–—
-35/8
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