Question

find the remainder when x³+6x²+3x-1 is divided by (x-2) using remainder theorem​

Answer 1

To find:

✠ The remainder when x³ + 6x² + 3x - 1 is divided by ( x - 2 ) using remainder theorem.

Solution:

For finding the remainder, using remainder theorem:

• Step 1: Put the divisor equal to zero and solve the equation obtained to get the value of its variable.
• Step 2: Substitute the value of the variable obtained in step ,1 in the given polynomial and simplified to get the required a remainder.

Let's find it...✧

➛ x - 2 = 0

➛ x = 2

Required remainder = Value of given polynomial x³ + 6x² + 3x - 1 at x = 2

Therefore,

➤ Remainder = 2³ + 6( 2 )² + 3( 2 ) - 1

➤ Remainder = 8 + 6( 4 ) + 6 - 1

➤ Remainder = 8 + 24 + 6 - 1

➤ Remainder = 32 + 6 - 1

➤ Remainder = 38 - 1

➤ Remainder = 37

∴ The remainder = 37

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