Question

Find the remainder when x3- 6x2 + 9x + 7 is divided by (x-1)​

Answer 1

Answer:

$\huge\mathfrak\red{Hey\ friend\ your\ answer\ is .............}$

$x - 1 = 0 => x = 1$

$\underline{Required\ remainder = Value\ of\ given\ polynomial\ x^3 -6x^2 +9x+7\ at\ x = 1}$

${\therefore {Remainder = (1)^3-6 (1)^2+9 (1)+7}}$

$=> Remainder = 1-6+9+7 = 11$

${\boxed{Remainder = 11 }}$

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Hope it helps u ...........

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Answer 2

${\pink{\boxed{\underline {Question :-}}}}$

Find the remainder when x3- 6x2 + 9x + 7 is divided by (x-1)

${\blue{\boxed{\underline {Answer :- }}}}$

$x - 1 = 0 \: \\ x = 1$

substitute the value of x in the equation given

${1}^{3} - 6( {1}^{2} ) + 9(1) + 7 \\ 1 - 6 + 9 + 7 \\ 17 - 6 = 11$

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hope it helps

: )