Question

Find the remainder when x³-ax²+4x-a is divided by(x-a)​

Answer 1

Answer:

x-a is divided by the polynomial

By remainder theorem

x-a =0

x=a

Putting the value of x in the given polynomial

a³ -a(a²)+4(a)-a

a³-a³+4a-a

3a

Hence 3a is the remainder.

Hope it helps you!

Answer 2

Answer: Reminder is 5a

Step-by-step explanation:

We have x  ^3  −ax  ^2  +6x−a  

Apply remainder theorem  

x−a=0

x=a

Put x=a in equation.  

(a)^ 3 −a(a)  ^2 +6a−a

=a^  3  −a^ 3 +6a−a

=6a−a

=5a

Then reminder is 5a