Question

find the remainder when x3 - ax2 + 6 x - a is divided by x-a​

Answer 1

Answer:

2a³+5a

Step-by-step explanation:

Here , p(x) = x³+ax²+6x-a,and the zero of x-a is a

So, p(a) = a³+a×a²+6×a-a

            = 2a³+5a

So, by the Remainder Theorem,2a³+5a is the remainder when x³+ax²+6x-a is divided by x-a