Find the remainder when x3-ax2+6x-a is devide by x-a
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Answers 5a
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Given:
Let, p(x) = x³–ax²+6x–a
and g(x) = x–a
To find:
p(x) ÷ g(x)
Solution:
p(x) / g(x) =(x³–ax²+6x–a) / x–a
On Long division
q(x) = x²+6
∴ r(x) = 5a [remainder]
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