Question

Find the remainder when x3-ax2+6x-a is divided by x-a​

Answer 1

Answer:

using remainder theorem

we

get.

put x=a

then

a^3-a^3+6a-a

then

remainder is 5a

ok

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Answer 2

Answer:

remainder=5a

Step-by-step explanation:

p(x)=$x^{3} - ax^{2} + 6x - a$

p(a)=$(a)^{3} - a(a)^{2} +6(a)-a$

=$a^{3} - a^{3} +6a-a$

=5a

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