Question

Find the remainder when x3-ax2+6x-a is divided by x-a​

Answer 1

$Let \: p(x) = x^{3} - ax^{2} + 6x - a$

$If \: p(x) \:divided \: by \: (x-a) \: then \: the \\remainder \:is \: p(a) \\ \blue { (By \: Remainder \: theorem )}$

$Remainder = p(a)\\</p><p>= a^{3} - a\times a^{2} + 6\times a - a \\= a^{3} - a^{3} + 6a - a \\= 5a$

Therefore.,

$\red { Remainder } \green {=5a}$

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Answer 2

Step-by-step explanation:

p(x)=x³-ax²+6x-a , and zero of x-a is a

p(a)=a³-a(a)²+6(a)-a

p(a)=a³-a³+6a-a

p(a)=5a

I Hope it's help you .