Question

Find the remainder when x3 – ax2 + 6x – a is divided by x-a.

Answer 1

Given:-

p(x) = x³ - ax² + 6x - a

Divisor = (x - a)

Therefore, x = a

Solution:-

p(a) = (a)³ - a(a)² + 6(a) - a

= a³ - a³ + 6a - a

= 5a

Hence, Remainder = 5a

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Answer 2

Let p(x) = x³−ax²+6x−a

x−a = 0

∴x = a

Remainder:

p(a) = (a)³−a(a²)+6(a)−a

= a³−a³+6a−a = 5a