Math, asked by bhardwajshilpa04, 9 months ago

Find the remainder when x3 – ax2 + 6x – a is divided by x-a.

Answers

Answered by Anonymous
5

Answer:

5a

Step-by-step explanation:

x-a=0

∴ x=a

Now, Placing the value of x in the given polynomial :-

x³-ax²+6x-a

= (a)³-a(a)²+6(a)-a

= a³-a³+6a-a

= 6a-a [ As a³ gets cancelled by -a³ }

5a is the answer.

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Answered by Anonymous
15

Let p(x) = x³−ax²+6x−a

x−a = 0

∴x = a

Remainder:

p(a) = (a)³−a(a²)+6(a)−a

= a³−a³+6a−a = 5a

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