Question

find the remainder when x3- ax2+6x-a is divided by x-a​

Answer 1

Step-by-step explanation:

explanation in the photo

Answer 2

Answer:

When x³ - ax² + 6x - a is divided by (x - a), we get the remainder as 5a.

Step-by-step explanation:

We are given,

p(x) = x³ - ax² + 6x - a is divided by (x - a)

Now,

If (x - a) is divided then,

x - a = 0

x = a

Thus,

putting x = a will give us the Remainder

Hence, Using Remainder theorem

p(x) = x³ - ax² + 6x - a

Now, x = a

p(a) = (a)³ - a(a)² + 6(a) - a

p(a) = a³ - a(a²) + 6a - a

p(a) = a³ - a³ + 5a

p(a) = 5a

Thus,

when x³ - ax² + 6x - a is divided by x - a, we get the remainder as 5a.