Question

Find the remainder when x3- ax2+ 6x- a is divided by x-a​

Answer 1

Answer:

5a

Step-by-step explanation:

By remainder theorem,

x - a = 0

x = a

p(x) = x^3 - ax^2 +6x -a

p(a) = a^3 - a(a^2) + 6a - a

= a^3 - a^3 + 5a

= 5a

Answer 2

Answer:

• a
• 5a

Step-by-step explanation:

Here, p(x)=x3 + ax2 + 6x−a,

and the zero of x−a is a

So, p(a)=a3+a×a2+6×a−a= 2a3 +5a

So, by the Remainder Theorem, 2a3+5a is the remainder when x3 +ax2+6x−a is divided by x−a.

Hope it was helpful