Find the remainder when x³ - ax²+ 6x -a is divided by x-a.
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Step-by-step explanation: Let p ( x ) = x³ - ax² + 6x - a
If ( x - a ) is a factor of p( x ), then x - a = 0 ⇒ x = a .
On substituting,
p ( a ) = a³ - a ( a² ) + 6 ( a ) - a
⇒ a³ - a³ + 6a - a
⇒ 6a - a
⇒ 5a is the remainder.
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