Question

Find the remainder when x3 – ax2 + 6x – a is divided by x – a.if the denominator is one third of first number.find the answer ?

Answer 1

Step-by-step explanation:

p(x)=x^{3} - ax^{2} + 6x - ax

3

−ax

2

+6x−a

p(a)=(a)^{3} - a(a)^{2} +6(a)-a(a)

3

−a(a)

2

+6(a)−a

=a^{3} - a^{3} +6a-aa

3

−a

3

+6a−a

=5a