find the remainder when- x³-ax² +6x-a is te divided by x-a
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:Answer:
Let f(x) = x³ - ax² + 6x - a
So,
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When,
f(a) = x³ - ax² + 6x - a
=> (a)³ - a×(a)² + 6×a - a
=> a³ - a³ + 6a - a
=> 5a
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