Question

Find the remainder, when
x3.-Px² + 6x-P is
divided by (x-P].​

Answer 1

Answer:

put your face into the

Step-by-step explanation:

is the correct answer

Answer 2

Question ⤵️

Find the remainder, when

x3.-Px² + 6x-P is

divided by (x-P].

Answer ⤵️

Answer: The required remainder is 5p.

Step-by-step explanation: We are given to find the remainder when the following polynomial is divided by (x - p) :

f(x)=x^3-px^2+6x-p.f(x)=x

3

−px

2

+6x−p.

Remainder theorem : When a polynomial p(x) is divided by the factor (x - a), then the remainder is given by p(a).

So, when f(x) is divided by (x - p), the remainder will be f(p).

Therefore, the required remainder is given by

\begin{gathered}f(p)\\\\=p^3-p\times p^2+6\times p-p\\\\=p^3-p^3+6p-p\\\\=5p.\end{gathered}

f(p)

=p

3

−p×p

2

+6×p−p

=p

3

−p

3

+6p−p

=5p.

Thus, the required remainder is 5p