Question

Find the remainder when x³-px²+bx-p is divided by x-p

Answer 1

Answer:

• bx-x

Step-by-step explanation:

• x-p)x^3 - px^2 + bx - p(x^2 + 1
• (+) x^3 - px^2

_(-)___(+)____________

• 0 + bx - p
• + x - p

_______________(-)__(+)_______

• bx - x + 0

1. therefore , remainder is bx - x

Answer 2

$\star{\mathbb{\underline{ANSWER:}}}$

$let \: p(x) = {x}^{3} - p{x}^{2} + 6x - p$

$Divisor \: = x – p$

$Zero \:of \: x – p = p$

${By \:remainder \:theorem,}$

$If \:p(x) \:is \:divided \:by \:(x – p), \:then \:the \:remainder \:is \:p(p)$

$p ( p) = {p}^{3} - p ({p})^{2}+ 6 (p) -p$

$={p}^{3}-{p}^{3}+6p- p$

$= 6p - p$

$=5p$