Question

Find the remainder when x3+ x2 + x + 1 is divided by x – 12 using remainder theorem.

Answer 1

Answer:

1885

Step-by-step explanation:

Here,

p(x) = x^3 + x^2 + x + 1, and the zero of x - 12 is 12

so,

p(12) = 12^3 + 12^2 + 12 + 1

       = 1728 + 144 + 12 + 1

       = 1885

So, by remainder theorem, 1885 is the remainder when x^3 + x^2 + x + 1 is divided by x - 12.

Answer 2

P(x)= x³+x³+x+1 and the zero of x-12=12

P(12)=12³+12²+12+1

=1728+144+12+1

=1885

Step-by-step explanation:

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