Find the remainder, when x⁴ + 4x³ – 5x² - 6x + 7 is divided by
(i) x-3
Answers
Answer:
133
Step-by-step explanation:
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Answer:
(i) 133
Step-by-step explanation:
Concept= Algebraic Division
Given= Divisor and Dividend in algebra
To find= Quotient
Explanation=
The given equation is x⁴ + 4x³ – 5x² - 6x + 7.
It has to be divided by x-3.
Dividend= x⁴ + 4x³ – 5x² - 6x + 7
Divisor= x-3
Division=
x-3| x⁴ + 4x³ – 5x² - 6x + 7 | x³ +7x² + 16x +42
x⁴ - 3x³
₋ ₊
7x³ - 5x²
7x³ - 21x²
⁻ ⁺
16x² - 6x
16x² - 48x
⁻ ⁺
42x + 7
42x - 126
⁻ ⁺
133.
Therefore the quotient is x³ +7x² + 16x +42 when x⁴ + 4x³ – 5x² - 6x + 7 is divided by x-3 and the remainder is 133.
The remainder is 133.
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