Question

find the remainder when x⁴+4x³-6x+7 is divided by x+3

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Answer 1

Answer:

133 is the answer.

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Answer 2

Answer:

The remainder is -2.

Step-by-step explanation:

x+3 ) $x^{4} +4x^{3}+0x^{2} -6x+7$ ( $x^{3} + 7x^{2} - 3x+3$

    (-)$x^{4} +3 x^{3$      

  _____________________  

       0  + $7x^{3} + 0x^{2}$

           (-) $7x^{3} +3x^{2}$

          _________________

                  (-) $-3x^{2} -6x\\-3x^{2} -9x$

                 ______________

                                   $3x+7$

                                (-)$3x-9$

                               ________

                                         -2 ------->remainder

∴-2 is remainder.