Question

find the remainder when xcube+3xsqaure+3x+1 is divided by x+1

Answer 1

6 is the remainder
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Answer 2

Understand that x^3 + 3x^2 + 3x + 1 = the dividend.

And x + 1 = the divisor.

We are dividing x^3 + 3x^2 + 3x + 1 by x + 1.

1. Put:

Divisor = 0

X + 1 = 0

Deduct 1 from both sides.

X = -1

2. Let p(x) = x^3 + 3x^2 + 3x + 1

Put x = -1

p(-1) = (-1)^3 + 3(-1)^2 + 3(-1) + 1

= -1 + 3 - 3 + 1

= 0

Therefore, the remainder = p(-1) = 0