Question

Find the remainder when xcube -axsquare +6x -a is divided by x-a

Answer 1

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Answer 2

Answer:

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Step-by-step explanation:

ANSWER ::

The zero of the polynomial x - a is given by

x-a = 0

So x = a

Let f(x) = x³- ax² + 6x - a

Now by the Remainder Theorem the required Remainder is

f(a) = a³- a×a² + 6a - a = a³- a³ + 5a = 5a