Math, asked by bhanwarlalsahu04, 5 months ago

find the remainder when xsquare-2x+1 is divided by (X+1/2)

Answers

Answered by kanikayadav4
0

Answer:

0

Step-by-step explanation:

for finding the remainder we need to use remainder theorom

for finding the remainder we need to use remainder theoromlet p(x)=x

for finding the remainder we need to use remainder theoromlet p(x)=x 2

for finding the remainder we need to use remainder theoromlet p(x)=x 2 +2x+1

for finding the remainder we need to use remainder theoromlet p(x)=x 2 +2x+1Here, the divisor is x+1 for dividend p(x), we need to equate it to 0 and put that value of x in p(x).

for finding the remainder we need to use remainder theoromlet p(x)=x 2 +2x+1Here, the divisor is x+1 for dividend p(x), we need to equate it to 0 and put that value of x in p(x).−x+1=0

for finding the remainder we need to use remainder theoromlet p(x)=x 2 +2x+1Here, the divisor is x+1 for dividend p(x), we need to equate it to 0 and put that value of x in p(x).−x+1=0∴x=−1

for finding the remainder we need to use remainder theoromlet p(x)=x 2 +2x+1Here, the divisor is x+1 for dividend p(x), we need to equate it to 0 and put that value of x in p(x).−x+1=0∴x=−1p(−1)=(−1)

for finding the remainder we need to use remainder theoromlet p(x)=x 2 +2x+1Here, the divisor is x+1 for dividend p(x), we need to equate it to 0 and put that value of x in p(x).−x+1=0∴x=−1p(−1)=(−1) 2

for finding the remainder we need to use remainder theoromlet p(x)=x 2 +2x+1Here, the divisor is x+1 for dividend p(x), we need to equate it to 0 and put that value of x in p(x).−x+1=0∴x=−1p(−1)=(−1) 2 +2(−1)+1=0

for finding the remainder we need to use remainder theoromlet p(x)=x 2 +2x+1Here, the divisor is x+1 for dividend p(x), we need to equate it to 0 and put that value of x in p(x).−x+1=0∴x=−1p(−1)=(−1) 2 +2(−1)+1=0Hence, remainder=0

Answered by Mridhula24
0

Answer = 0

Step-by-step explanation: for finding the remainder we need to use remainder theorem  let p(x)=x   2  +2x+1  .Here, the divisor is x+1 for dividend p(x), we need to equate it to 0 and put that value of x in p(x). −x+1=0 ∴x=−1 p(−1)=(−1)  2  +2(−1)+1=0

Hence, remainder=0

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