find the remainder when y^3+4y^2-3y+10 is divided by y+4
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Answer:
22 is the remanider
Step-by-step explanation:
first multiply with y^2 so we get y^3+4y^2 which get cancelled
then multiply with -3 then we get -3y-12 then -3y get cancelled and remainder will be 10+12 i.e. 22
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