Question

find the remainder when y^3 + y^2 - 2 y + 5 is divided by y- 5​

Answer 1

Step-by-step explanation:

Remainder =145 Again, We should evaluate p(5) Let p(y)=y 3 +y 2 −2y+5 ∴p(5)=5 3 +5 2 −2×5+5=125+25−10+5 =145 Thus, we find that p(5) is the remainder when p(y) is divided by y−5.

Answer 2

Step-by-step explanation:

Remainder = 145

Again, We should evaluate p(5)

Let p(y) = y3 + y² - 2y + 5

-. p(5) = 53 +52 - 2 × 5+5

= 125 + 25 10 + 5

= 145

Thus, we find that p(5) is the remainder when p(y) is divided by y - 5.

y² + 6y + 28

y-5

y² + y2-2y + 5

(³ - 5y²)

6y²-2y + 5

- (6y²- 30y)

28y + 5 - (28v - 140)

145