Question

Find the remainder when y³ +4y² -3y + l0 is divided by y+4​

Answer 1

☯GIVEN

• $\bf{p(y) =y^3+4y^2-3y+10}$

• $\bf{g(y) = y+4}$

☯TO FIND :

• Reminder.

➲SOLUTION :

• By Remainder Theorem :

Suppose g(y) = 0.

$\longrightarrow{ \tt{y+4 = 0}}$

$\longrightarrow{ \tt{y = 0 - 4}}$

$\longrightarrow{ \bf{y = -4}}$

Substituting the value of y :

$\longrightarrow{\tt{p(y) =y^3 +4y^2-3y+10 }}$

$\longrightarrow{\tt{p( - 4) =( - 4)^3 + 4( - 4)^2 - 3 \times ( - 4)+10}}$

$\longrightarrow{\tt{p( - 4) = - 64 + 4 \times 16 + 12 + 10}}$

$\longrightarrow{\tt{p( - 4) = - 64 + 64+ 12 + 10}}$

$\longrightarrow{\tt{p( - 4) = - 64 + 86}}$

$\leadsto{\underline{ \pink{\boxed{\bf{p(-4) = 22}}}}}$

$\huge{\green{\therefore}}$ Remainder = 22.

Answer 2

Answer:

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