Question

- Find the remainder whenx²-ax²+6x-a is divided by x-2​

Answer 1

Answer:

Step-by-step explanation:

Let p (x ) = x³ - ax² + 6x - a = 0

If ( x - 2 ) is a factor of p ( x ),then x - 2 = 0⇒ x = 2.

On substituting,

p ( 2 ) = ( 2 )³ - a ( 2)² + 6 ( 2) - a = 0

⇒ 8 - 4a + 12 - a = 0

⇒ 20 - 5a = 0

⇒ 5a = 20 (∵ transposing )

⇒ a = 20 / 5 (∵ transposing )

⇒ a = 4 is the answer.