find the remainder where the polynomial 2x^3-3x^2+5x-7 is the x-2
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Answered by
0
Answer:
7
Step-by-step explanation:
x-2=0
x=2
p(x)=2x^3-3x^2+5x-7
p(2)=2(2)^3-3(2)^2+5(2)-7
=16-12+10-7
=7
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