Math, asked by TinnDoe, 9 days ago

Find the remainder, where x ^ 3 - 3x ^ 2 + 3x - 1 is divided by (x - 1)​

Answers

Answered by anushkapandey90
2

Hence by the remainder theorem, 0 is the remainder when x3 + 3x2 + 3x + 1 is divided by x + 1. We can also say that x + 1 is a factor of x3 + 3x2 + 3x + 1. (ii) The root of x - (1/2) = 0 is 1/2. Hence by the remainder theorem, 27 / 8 is the remainder when x3 + 3x2 + 3x + 1 is divided by x.

Answered by surthiraj
1

Hence by the remainder theorem, 0 is the remainder when x3 + 3x2 + 3x + 1 is divided by x + 1. We can also say that x + 1 is a factor of x3 + 3x2 + 3x + 1. (ii) The root of x - (1/2) = 0 is 1/2. Hence by the remainder theorem, 27 / 8 is the remainder when x3 + 3x2 + 3x + 1 is divided by x.

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