Question

find the remainder (without division) on dividing f(x) by(2x + 1 ) where .. f(x) = 3x^3-7x^2+4x+11..

Answer 1

By Remainder Theorem,

2x = -1

x = $\frac{-1}{2}$

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Remainder = 3(-1/2)³ -7(-1/2)² + 4(-1/2) + 11

Remainder = -3/8 -7/4 - 2 + 11

Remainder = -3/8 -7/4 + 9

Remainder = $\frac{-3 - 14+ 72}{8}$

Remainder = $\frac{55}{8}$



i hope this will help you


-by ABHAY

Answer 2

Heya friend.....☺

Here is your solution.....❇❇

Thanks.....☺☺