Find the remainder (without division) when
4x3 –3x2+2x-4 is divided by x+2
Answers
Answered by
2
Step-by-step explanation:
Suppose length of a side in the rhombus ABCD is a (AB=BC=CD=DA=a), then 4a=180 or a= 45 and the area is given by 0.5a^2sinABC=315 or sinABC=630/2025=14/45
The altitude = BC.sinABC=45.(14/45)=14
Hence answer is 14
Answered by
1
x+2=0
x = -2
4x³ - 3x² + 2x - 4
p(x) = 4x³-3x²+2x-4
p(-2) = 4(-2)³-3(2)²+2×2-4
p(-2) = -32 - 12 +4-4
remainder = -64
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