Find the remainder (without division) when 8+5x+1 is divisible by (x-10)
Answers
Answered by
3
given equation f(x) = 8+5x+1
as it is given (x-10)
by the remainder theorem , we get
x-10
or , alpha = 10
therefore , by assuming the value of alpha as x ,we get
f(10) = 8+5(10)+1
= 8+50+1
= 59 is the remainder....
this sum is done by following the remainder theorem..
plz mark me as brainliest...
Answered by
1
Answer:
check solution
Step-by-step explanation:
the remainder found by putting g(x)= 0 in p(x) if become zero then g(x) is factor of p(x)
so x-10=0
Therefore x=10
by putting x=10 in g(x) we get
8+5(10)+1= 59
so since the remainder obtained by putting g(x)=0 is not zero therefore g(x) is not a factor of p(x)
hope it will help uh pls mark me as brainliest only if uh understand the answer
Similar questions