Find the remainders when y³ + y² – 2y + 5 is divided by (y – 5) and (y – 2).
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Remainder = 145
Again, we should evaluate p(5)
Let p(y) = y3 + y2 - 2y + 5
∴ p(5) = 53 + 52 - 2 x 5 + 5
= 125 + 25 - 10 + 5
= 145
Thus , we find that p(5) is the remainder when
p(y) is divided by y - 5 .
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