Find the remaining zeroes of the polynomial when x^4 -7x^3+17x^2-17x+6,if two of its zeroes are 3 and 1
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vsjevsun
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Let other zeroes are a,b
Then a+b+4 = 7→ a+b = 3
a.b.3 = 6 → ab = 2.
So, a=1, b=2 or a=2, b=1
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