Question

find the remandar when xsqare 3 +3xsqare +3x +1 is divided by (i)X+π
(ii)x-1
2
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Answer 1

Answer:

(i)X+π

Apply remainder theorem

=>x + π =0

=> x = - π

Replace x by – π we get

$=>x^3+3x^2 + 3x + 1$

$=>(- π)^3 + 3(-π)^2 + 3(-π) + 1$

$=> - π^3 + 3π^2 - 3^π + 1$

Remainder is - π3 + 3π2 - 3π + 1

(ii)x-1

Apply remainder theorem

=>x - 1 =0

=> x = 1

Replace x by 1 we get

$=>x3+3x^2 + 3x + 1$

$=>(1)^3 + 3(1)^2 + 3(1) + 1$

=> 1 + 3 + 3 + 1

=> 8

Remainder is 8.

Answer 2

Answer:

Remainder = 8 ................