Question

Find the remiander when p(x) = x^3-ax^2+6x-a is divided bi x-a

Answer 1

Srry can't divide but it can also be solved by factor theorum

p(x)=x³-ax²+6x-a

g(x)=x-a

p(a)=(a)³-a(a)²+6*a-a

     =a³-a³+6a-a

     =6a-a

    =5a

so the remainder is 5a

Answer 2

Hey friend,

The division is given in the attachment below...

Hope it helps