Math, asked by anuprarthana3200, 1 month ago

find the reminder by reminder theorem if p(x)=4x³+3x²+2x-9 is divisible by (x-2)

Answers

Answered by ushadevi96086
0

Step-by-step explanation:

Let g(x) = x - 2.Then,

g(x) = 0

= x - 2 = 0

= x = 2

By the remainder theorem, we know that when p(x) is divided by g(x) the remainder is p(2)

Now, p(2) = 4×(2)^3 + 3×(2)^2 + 2×2 - 9

= 4×8 + 3×4 + 4 - 9

= 32 + 12 - 5

= 39

Hence, the remainder is 39

Answered by pulakmath007
0

SOLUTION

TO DETERMINE

The reminder by reminder theorem if p(x) = 4x³ + 3x² + 2x - 9 is divisible by ( x - 2 )

EVALUATION

Here the given polynomial is

p(x) = 4x³ + 3x² + 2x - 9

Let f(x) = x - 2

For Zero of the polynomial f(x) we have

f(x) = 0

⇒ x - 2 = 0

⇒ x = 2

Hence by remainder Theorem the required Remainder when p(x) is divided by f(x) is

= p(2)

 \sf{ = 4 \times  {(2)}^{3} + 3 \times  {(2)}^{2}  + (2 \times 2) - 9 }

 \sf{ =( 4 \times  8)+ (3 \times  4)  + (2 \times 2) - 9 }

 \sf{ =32 + 12 + 4 - 9 }

 \sf{ =39 }

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