Question

Find the reminder if x-2 of divides 4x^2+3x+5

Answer 1

Here we can find out remainder by 2 methods:-

1] By long division method (In the attachment)

2] By remainder theorem.

So We have solve by long division method in the attachment.

So here lets solve by remainder theorem.

$\therefore$ By remainder theorem we get,

$\tt\longrightarrow x-2 = 0. \\ \\ \tt\longrightarrow x = 2.$

So lets put the value of x in the given polynomial:-

$\tt\mapsto 4x^2 +3x+5. \\ \\ \tt\mapsto 4(2)^2+3(2)+5. \\ \\ \tt=4(4)+6+5. \\ \\ \tt =16+6+5. \\ \\ \tt =22+5. \\ \\ \tt =27.$

Therefore the Remainder is 27.

Answer 2

Answer:

27 is remainder

Please find attachment

Hope Helps You