Find the reminder obtained on dividing p(x)=x3+1by x+1
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Answer:
Given f(x)=x^3+1
q(x)=x+1
From q(x) we get the value of x= (-1)
Put the same value in f(x) we get
f(-1)=(-1)^3+1
f(-1)=(-1)+1
f(x)=0
The remainder is 0
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