Math, asked by nandhanak5558, 2 months ago

Find the reminder when 4xcube-3xsquare+3x-2 is divided by x-1 and x+1?

Answers

Answered by saubhagyasharmacool
0

Answer:

4x^3-3x^2+3x-2/x-1

x-1=0

x=0+1

x=1

4x^3-3x^2+3x-2

=4×1^3-3×1^2+3×1-2

=4×1-3×1+3-2

=4-3+3-2

=1+3-2

=4-2

=2

4x^3-3x^2+3x-2/x+1

x+1=0

x=0-1

x=-1

4x^3-3x^2+3x-2

=4×-1^3-3×-1^2+3×-1-2

=4×-1-3×1+-3-2

=-4-3-3-2

=-7-3-2

=-10-2

=-12

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