Question

Find the reminder when p(x) = x^3

+ 3x² + 3x + 1 is divide by g(x) = x - 1/2​

Answer 1

Step-by-step explanation:

The root of x - (1/2) = 0 is 1/2.

p(1/2) = (1/2)3 + 3(1/2)2 + 3(1/2) + 1

= 1/8 + 3/4 + 3/2 + 1

= (1 + 6 + 12 + 8)/8 = 27/8

Hence by the remainder theorem, 27 / 8 is the remainder when x3 + 3x2 + 3x + 1 is divided by x.